lab chem asg
Description
I uploaded the lab manual and lab format. You should write a lab report in same with lab format. In conclusion part we need to find percent yield. Just put the calculations below
1.12 . 1g/1.36.15 g/mol = 0.082 x 181= 1.49 g
Percent Yield=Actual Yield/ Theoretical Yield x 100%
0.17 g filter paper
1-01.17= 0.83g
= 0.83/1.49 x 100%= 55.6%

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